Question

Giúp mik,please

Answer 1

a: \(\frac{64x^3+1}{16x^2-1}=\frac{A}{4x-1}\)

=>\(\frac{\left(4x+1\right)\left(16x^2-4x+1\right)}{\left(4x-1\right)\left(4x+1\right)}=\frac{A}{4x-1}\)

=>\(\frac{A}{4x-1}=\frac{16x^2-4x+1}{4x-1}\)

=>\(A=16x^2-4x+1\)

b: \(\frac{5x-2}{B}=\frac{10x^2-29x+10}{10x^2+27x+5}\)

=>\(\frac{5x-2}{B}=\frac{10x^2-25x-4x+10}{10x^2+25x+2x+5}\)

=>\(\frac{5x-2}{B}=\frac{\left(2x-5\right)\left(5x-2\right)}{\left(2x+5\right)\left(5x+1\right)}\)

=>\(B=\frac{\left(2x+5\right)\left(5x+1\right)\left(5x-2\right)}{\left(2x-5\right)\left(5x-2\right)}=\frac{\left(2x+5\right)\left(5x+1\right)}{2x-5}\)