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\(\dfrac{x-3y}{x+y}=\dfrac{1}{3}\)
=>3x-9y=x+y
=>2x=10y
=>x/y=5
=>x=5y
\(\dfrac{x+3y}{x-y}=\dfrac{5y+3y}{5y-y}=2\)
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\(\dfrac{x-3y}{x+y}=\dfrac{1}{3}\)
=>3x-9y=x+y
=>2x=10y
=>x/y=5
=>x=5y
\(\dfrac{x+3y}{x-y}=\dfrac{5y+3y}{5y-y}=2\)