Câu 4:
a: \(A=\dfrac{-7}{19}\cdot\left(\dfrac{8}{11}+\dfrac{3}{11}\right)-\dfrac{12}{19}=\dfrac{-7}{19}-\dfrac{12}{19}=-1\)
b: \(C=\left(\dfrac{67}{111}+\dfrac{2}{33}-\dfrac{15}{117}\right)\cdot\dfrac{-4+3+1}{12}=0\)
Đúng 2
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