giúp mik vs
\(8,\Rightarrow\left(x-\dfrac{1}{2}\right)^3=\dfrac{3}{8}-\dfrac{1}{2}=-\dfrac{1}{8}=\left(-\dfrac{1}{2}\right)^3\\ \Rightarrow x-\dfrac{1}{2}=-\dfrac{1}{2}\Rightarrow x=0\\ 11,\Rightarrow\left(x-2\right)\left(2-x\right)=33\left(-297\right)\\ \Rightarrow\left(x-2\right)^2=9801\Rightarrow\left[{}\begin{matrix}x-2=99\\x-2=-99\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=101\\x=-97\end{matrix}\right.\)
8) \(\Rightarrow\left(x-\dfrac{1}{2}\right)^3+\dfrac{1}{2}=\dfrac{3}{8}\)
\(\Rightarrow\left(x-\dfrac{1}{2}\right)^3=-\dfrac{1}{8}\)
\(\Rightarrow x-\dfrac{1}{2}=-\dfrac{1}{2}\Rightarrow x=0\)
11) ĐK: \(x\ne2\)
\(\Rightarrow\left(x-2\right)\left(2-x\right)=-297.33\)
\(\Rightarrow-x^2+4x-4=-9801\)
\(\Rightarrow-\left(x-101\right)\left(x+97\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=101\left(tm\right)\\x=-97\left(tm\right)\end{matrix}\right.\)
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