\(=\dfrac{3}{5}+\dfrac{-17}{45}=\dfrac{27-17}{45}=\dfrac{10}{45}=\dfrac{2}{9}\)
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= \(\dfrac{3}{5}+\dfrac{-17}{45}\)
= \(\dfrac{27}{45}+\dfrac{-17}{45}\)
= \(\dfrac{10}{45}=\dfrac{2}{9}\)
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\(\dfrac{3}{5}+\dfrac{1}{5}.\dfrac{-17}{9}\)
\(=\dfrac{3}{5}+\left(\dfrac{-17}{45}\right)\)
\(=\dfrac{2}{9}\)
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