Question

Giúp mik bài 2 với

Answer 1

Bài 1: 

a: \(P=\dfrac{x+\sqrt{x}-2}{\sqrt{x}\left(\sqrt{x}+2\right)}\cdot\dfrac{\sqrt{x}+1}{\sqrt{x}-1}=\dfrac{\sqrt{x}+1}{\sqrt{x}}\)

b: \(\Leftrightarrow P=\dfrac{2\sqrt{x}+5}{2}\)

\(\Leftrightarrow\dfrac{2\sqrt{x}+5}{2}=\dfrac{\sqrt{x}+1}{\sqrt{x}}\)

\(\Leftrightarrow2x+5\sqrt{x}=2\sqrt{x}+2\)

\(\Leftrightarrow2\sqrt{x}+3\sqrt{x}-2=0\)

=>x=1/4