Question

Giúp iem vs. x+(x+1)+(x+2)+....+(x+100)=20869

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Answer 1

x+(x+1)+(x+2)+...+(x+100)=20869

x+(x x 100)+(1+2+3+...+100)=20869

(x x 101)+(100x(100+1)=20869

(x x 101)+(100x101)=20869

(x x 101)+10100=20869

x x 101=20869-10100

x x 101=10769

x=10769:101

x=\(\dfrac{10769}{101}\)

Answer 2

Cảm ơn ạ@nguyễn nhân dương

Answer 3

x+(x+1)+(X+2)+....+(x+100) = 20869

X x 101 +( 1+2+...+100) = 20869

X x 101 + 5050 = 20869

X x 101 = 15819

x = 15819 : 101

x= ......

Answer 4

 x+(x+1)+(x+2)+....+(x+100)=20869

=> 101x + ( 100-1) nhân 100 : 2 = 20869

=> 101x +4950 = 20869

=> 101x = 20869-4950

=> 101x =15 919

=> x =15 919:101 =15919/101

Vậy x = 15919/101

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