Question

giúp em với các chiến thần  :<

(-36) + 45 + [32 x (-2) - (-155) ]

tính bình thường ạ :<

 

Answer 1

\(\left(-36\right)+45+\left[32.\left(-2\right)-\left(-155\right)\right]\\ =\left(-36\right)+45+\left[-64-\left(-155\right)\right]\\ =\left(-36\right)+45+\left[-64+155\right]\\ =\left(-36\right)+45+91\\ =9+91\\ =100\)

Answer 2

(-36) + 45 + [32 . (-2) - (-155)]

= (-36) + 45 +[(-64) + 155]

= (-36) + 45 - 64 + 155

=(-36 - 64) + (45 + 155)

= -100 + 200

= 100

Answer 3

\(\left(-36\right)+45+\left[32\times\left(-2\right)-\left(-155\right)\right]\)

\(=\left(-36\right)+45+\left(-64\right)+155\)

\(=\left[\left(-36\right)+\left(-64\right)\right]+\left(45+155\right)\)

\(=-100+200\)

\(=100\)

Answer 4

\(\left(-36\right)+45+\left[32\cdot\left(-2\right)-\left(-155\right)\right]\)

\(=\left(-36\right)+45+\left[-\left(32\cdot2\right)-\left(-155\right)\right]\)

\(=\left(-36\right)+45+\left[\left(-64\right)-\left(-155\right)\right]\)

\(=\left(-36\right)+45+\left[\left(-64\right)+155\right]\)

\(=\left(-36\right)+45+\left[155-64\right]\)

\(=\left(-36\right)+45+91\)

\(=45-36+91\)

\(=9+91\)

\(=100\)