Question

giúp em với ạ

Answer 1

a: ĐKXĐ: x<>-1; x<>0; x<>1

b: \(P=\left(\dfrac{x^2-2}{x-1}-\dfrac{1}{x}\right)\cdot\dfrac{x^2}{x+1}\)

\(=\dfrac{x^3-2x-x+1}{x\left(x-1\right)}\cdot\dfrac{x^2}{x+1}\)

\(=\dfrac{x^2\left(x^3-3x+1\right)}{x\left(x-1\right)\left(x+1\right)}\)