Question

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Answer 1

Answer 2

Câu 6: 

a: Ta có: \(x\cdot\dfrac{3}{2}-3=\dfrac{1}{2}\)

\(\Leftrightarrow x\cdot\dfrac{3}{2}=\dfrac{7}{2}\)

hay \(x=\dfrac{7}{3}\)

b: Ta có: \(\left|2x-1\right|=2\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=2\\2x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=3\\2x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)