\(\left(2x-3\right)^8=\left(2x-3\right)^6\)
\(\left(2x-3\right)^8-\left(2x-3\right)^6=0\)
\(\left(2x-3\right)^6.\left[\left(2x-3\right)^2-1\right]=0\)
\(\left(2x-3\right)^6=0\) hoặc \(\left(2x-3\right)^2-1=0\)
*) \(\left(2x-3\right)^6=0\)
\(2x-3=0\)
\(2x=0+3\)
\(2x=3\)
\(x=\dfrac{3}{2}\)
*) \(\left(2x-3\right)^2-1=0\)
\(\left(2x-3\right)^2=0+1\)
\(\left(2x-3\right)^2=1\)
\(\left(2x-3\right)^2=1^2\) hoặc \(\left(2x-3\right)^2=\left(-1\right)^2\)
+) \(\left(2x-3\right)^2=1^2\)
\(2x-3=1\)
\(2x=1+3\)
\(2x=4\)
\(x=\dfrac{4}{2}\)
\(x=2\)
+) \(2x-3=-1\)
\(2x=-1+3\)
\(2x=2\)
\(x=\dfrac{2}{2}\)
\(x=1\)
Vậy \(x=1\); \(x=\dfrac{3}{2}\); \(x=2\)
\(\Leftrightarrow\left(2x-3\right)^6\left[\left(2x-3\right)^2-1\right]=0\)
=>(2x-3)6(2x-2)(2x-4)=0
hay \(x\in\left\{1;2;\dfrac{3}{2}\right\}\)
