Question

giúp em bài 3  vs ạ, em c.ơn

Answer 1

Bài 3:

Ta có: \(A=\dfrac{\sqrt{x}-5}{\sqrt{x}+2}=\dfrac{\sqrt{x}+2-7}{\sqrt{x}+2}=1-\dfrac{7}{\sqrt{x}+2}\)

A nguyên khi \(\dfrac{7}{\sqrt{x}+2}\) nguyên:

\(\Rightarrow7\) ⋮ \(\sqrt{x}+2\)  

\(\Rightarrow\sqrt{x}+2\inƯ\left(7\right)=\left\{1;-1;7;-7\right\}\)

Mà: \(\sqrt{x}+2\ge2\)

\(\Rightarrow\sqrt{x}+2\in\left\{7\right\}\)

\(\Rightarrow x\in\left\{25\right\}\)