\(\dfrac{x}{x-2}-\dfrac{2}{x-3}>1\\ \Leftrightarrow\dfrac{x\left(x-3\right)-2\left(x-2\right)}{\left(x-2\right)\left(x-3\right)}>1\\ \Leftrightarrow x^2-3x-2x+4>x^2-5x+6\\ \Leftrightarrow x^2-5+4>x^2-5x+6\\ \Leftrightarrow4>6\left(vô.lí\right)\)
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