Question

giúp e giải bài này ạ e c. ơn ac

Answer 1

1: ĐKXĐ: x>=0; \(x\notin\left\{4;1\right\}\)

\(P=\dfrac{x-4\sqrt{x}+3-\left(2x-5\sqrt{x}+2\right)+x-2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)}\)

\(=\dfrac{2x-4\sqrt{x}+1-2x+5\sqrt{x}-2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)}=\dfrac{1}{\sqrt{x}-2}\)

2: Để P>=2 thì P-2>=0

\(\Leftrightarrow\dfrac{1-2\sqrt{x}+4}{\sqrt{x}-2}>=0\)

\(\Leftrightarrow\dfrac{2\sqrt{x}-5}{\sqrt{x}-2}< =0\)

=>4<x<=25/4

Answer 2

3, \(\sqrt{x}-2\inƯ\left(1\right)=\left\{\pm1\right\}\)

\(\sqrt{x}-2\)	1	-1
x	9	1(loại)