ĐKXĐ: \(x\notin\left\{\dfrac{1}{2};-\dfrac{1}{2}\right\}\)
\(\dfrac{8x^2}{3\left(1-4x^2\right)}=\dfrac{2x}{6x-3}-\dfrac{1+8x}{4+8x}\)
=>\(\dfrac{-8x^2}{3\left(2x-1\right)\left(2x+1\right)}=\dfrac{2x}{3\left(2x-1\right)}-\dfrac{8x+1}{4\left(2x+1\right)}\)
=>\(\dfrac{-8x^2\cdot4}{12\left(2x-1\right)\left(2x+1\right)}=\dfrac{2x\cdot4\left(2x+1\right)}{12\left(2x-1\right)\left(2x+1\right)}-\dfrac{3\left(2x-1\right)\left(8x+1\right)}{12\left(2x-1\right)\left(2x+1\right)}\)
=>\(-32x^2=8x\left(2x+1\right)-3\left(16x^2-6x-1\right)\)
=>\(-32x^2=16x^2+8x-48x^2+18x+3\)
=>26x+3=0
=>\(x=-\dfrac{3}{26}\left(nhận\right)\)
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