Question

giúp bài 1

Answer 1

Bài 1:

a: \(P=\left(\frac{1}{\sqrt{x}+2}+\frac{\sqrt{x}+3}{x-4}\right):\left(\frac{\sqrt{x}-1}{\sqrt{x}-2}-1\right)\)

\(=\frac{\sqrt{x}-2+\sqrt{x}+3}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}:\frac{\sqrt{x}-1-\sqrt{x}+2}{\sqrt{x}-2}\)

\(=\frac{2\sqrt{x}+1}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\cdot\frac{\sqrt{x}-2}{1}=\frac{2\sqrt{x}+1}{\sqrt{x}+2}\)

b: \(P=\frac32\)

=>\(\frac{2\sqrt{x}+1}{\sqrt{x}+2}=\frac32\)

=>\(2\left(2\sqrt{x}+1\right)=3\left(\sqrt{x}+2\right)\)

=>\(4\sqrt{x}+2=3\sqrt{x}+6\)

=>\(\sqrt{x}=4\)

=>x=16(nhận)