Sửa đề: \(\dfrac{x-2}{x+3}-\dfrac{x+2}{3-x}=\dfrac{2x^2+6}{x^2-9}\)
=>(x-2)/(x+3)+(x+2)/(x-3)=2x^2+6/x^2-9
=>\(\left(x-2\right)\left(x-3\right)+\left(x+2\right)\left(x+3\right)=2x^2+6\)
=>\(2x^2+6=x^2-5x+6+x^2+5x+6=2x^2+12\)
=>6=12(loại)
Giải PT sau:
\(\dfrac{x}{3}-\dfrac{2x+1}{2}=\dfrac{x}{6}-\dfrac{x}{4}\)
giải pt:
\(\dfrac{x}{2x-6}+\dfrac{x}{2x+2}=\dfrac{-2x}{\left(3-x\right)\left(x+1\right)}\)
câu 1 giải các pt sau
a,3x-12=0 b,(x-2)(2x+3)=0 c,\(\dfrac{x+2}{x-2}-\dfrac{6}{x+2}=\dfrac{x^2}{x^2-4}\)
Giải các pt sau:
1)\(\dfrac{2x+1}{x^2-4}+\dfrac{2}{x+1}=\dfrac{3}{2-x}\)
2)\(\dfrac{3x+1}{1-3x}+\dfrac{3+x}{3-x}=2\)
3)\(\dfrac{8x-2}{3}=1+\dfrac{5-2x}{4}\)
4)
\(\dfrac{x}{x+1}-\dfrac{2x+3}{x}=\dfrac{-3}{x+1}-\dfrac{3}{x}\)
5)\(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{4}{x^2-1}\)
6)\(\dfrac{2x+5}{2x}-\dfrac{x}{x+5}=0\)
giúp mình với cám ơn
Giải PT: \(\dfrac{2x-1}{3}\) - \(\dfrac{x-1}{2}\) + \(\dfrac{x+1}{6}\) = 1
giải pt bậc nhất một ẩn
\(\dfrac{2x+1}{6}\)-\(\dfrac{x-2}{4}\)=\(\dfrac{3-2x}{3}\)-x
giải các phương trình sau
a, 3(x-1) -3=2(x+3)
b, \(\dfrac{x+4}{4}-\dfrac{x+3}{3}=\dfrac{x+6}{6}\)
c,\(\left(2x-1\right)^2-x^2=0\)
d,\(\dfrac{x}{x+3}-\dfrac{2x}{x-3}-\dfrac{3x}{9-x^2}=0\)
Giải các phương trình sau: (TM ĐK)
1) \(\dfrac{11}{x}=\dfrac{9}{x+1}+\dfrac{2}{x-4}\)
2) \(\dfrac{14}{3x-12}-\dfrac{2+x}{x-4}=\dfrac{3}{8-2x}-\dfrac{5}{6}\)
3) \(\dfrac{x+5}{x^2-5x}-\dfrac{x+25}{2x^2-50}=\dfrac{x-5}{2x^2+10}\)
4) \(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{16}{x^2-1}\)
5) \(\left(1-\dfrac{x-1}{x+1}\right)\left(x+2\right)=\dfrac{x+1}{x-1}+\dfrac{x-1}{x+1}\)
mng giúp mk bài này nha. Cảm ơn bạn nhiều
\(\dfrac{x}{2x+2}\) - \(\dfrac{2x}{x^2-2x-3}\) = \(\dfrac{x}{6-2x}\)
\(\dfrac{2x-3}{x+5}\) \(\ge\) 3
Giải PT và BPT
giải pt sau
a)\(\dfrac{60}{x}=\dfrac{4}{3}+\dfrac{60-x}{x+4}\)
b)\(\dfrac{100}{x}-\dfrac{100}{x+20}=\dfrac{5}{6}\)
c)\(\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}=\dfrac{8}{4x^2-1}\)
Helppppp
