\(\Leftrightarrow x+10+3\left(x-2\right)+2\left(x+1\right)=\left(x-2\right)\left(x+1\right)\)
\(\Leftrightarrow x^2-x-2=x+10+3x-6+2x+2=6x+6\)
\(\Leftrightarrow x^2-7x-8=0\)
=>(x-8)(x+1)=0
=>x=8
\(\left(x\ne2;-1\right).\\ PT\Leftrightarrow\dfrac{x+10+3\left(x-2\right)+2\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}=1.\\ \Leftrightarrow\dfrac{x+10+3x-6+2x+2}{\left(x-2\right)\left(x+1\right)}=1.\\ \Leftrightarrow\dfrac{6x+6}{\left(x-2\right)\left(x+1\right)}=1.\\ \Leftrightarrow\dfrac{6\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}=1.\\ \Leftrightarrow\dfrac{6}{x-2}-1=0.\\ \Leftrightarrow\dfrac{6-x+2}{x-2}=0.\\ \Rightarrow8-x=0.\\ \Leftrightarrow x=8\left(TM\right).\)
