\(\dfrac{5}{x+1}+\dfrac{2x}{\left(x+1\right)\left(x-4\right)}=\dfrac{2}{x-4}\) ĐKXĐ \(\left\{{}\begin{matrix}x\ne-1\\x\ne4\end{matrix}\right.\)
\(\Leftrightarrow\dfrac{5\left(x-4\right)}{\left(x+1\right)\left(x-4\right)}+\dfrac{2x}{\left(x+1\right)\left(x-4\right)}=\dfrac{2\left(x+1\right)}{\left(x-4\right)\left(x+1\right)}\)
`=> 5(x-4) +2x=2(x+1)`
`<=> 5x-20 +2x=2x+2`
`<=> 7x-20=2x+2`
`<=> 7x-2x=2+20`
`<=> 5x=22`
`<=>x=22/5`
Vậy pt đã cho có nghiệm `x=22/5`
`5/[x+1]+[2x]/[(x+1)(x-4)]=2/[x-4]` `ĐK: x ne -1; 4`
`=>5(x-4)+2x=2(x+1)`
`<=>5x-20+2x=2x+2`
`<=>5x=22`
`<=>x=22/5` (t/m)
