a: ĐKXĐ: \(x\notin\left\{2;-2\right\}\)
\(\dfrac{x+2}{x-2}-\dfrac{x-2}{x+2}=\dfrac{16}{x^2-4}\)
=>\(\dfrac{\left(x+2\right)^2-\left(x-2\right)^2}{\left(x-2\right)\left(x+2\right)}=\dfrac{16}{\left(x-2\right)\left(x+2\right)}\)
=>\(\left(x+2\right)^2-\left(x-2\right)^2=16\)
=>\(\left(x+2+x-2\right)\left(x+2-x+2\right)=16\)
=>\(4\cdot2x=16\)
=>x=2(loại)
b: ĐKXĐ: \(x\notin\left\{2;3\right\}\)
\(\dfrac{x+3}{x-2}+\dfrac{x+2}{x-3}=2\)
=>\(\dfrac{\left(x+3\right)\left(x-3\right)+\left(x+2\right)\left(x-2\right)}{\left(x-2\right)\left(x-3\right)}=2\)
=>\(\dfrac{x^2-9+x^2-4}{x^2-5x+6}=2\)
=>\(2\left(x^2-5x+6\right)=2x^2-13\)
=>\(2x^2-10x+12=2x^2-13\)
=>-10x+12=-13
=>-10x=-25
=>x=2,5(nhận)
