Question

Giải phương trình (x- 1). (2x – 3) – 2x2 = 0

Answer 1

(x-1) . (2x -3) - 2x^{2} = 0

2x^{2} - 3x - 2x + 3 - 2x^{2} = 0

-5x +3 = 0

-5x= -3 

x= \dfrac{3}{5}

Answer 2

`(x - 1)(2x - 3) - 2x^2 = 0`

`2x^2 - 3x - 2x + 3 - 2x^2 = 0`

`(2x^2 − 3x − 2x + 3)− 2x^2 = 0`

`-5x + 3 = 0`

`x= 3/5`

Answer 3

`(x - 1)(2x - 3) - 2x^2 = 0`

`=> x . 2x - x . 3 - 1 . 2x + 1 . 3 -2x^2=0`

`=> 2x^2-3x-2x+3 - 2x^2  = 0`

`=> -5x +3  = 0`

`=> -5x = -3`

`=> x = 3/5`

Vậy: `S={3/5}`