\(\frac{x}{30+3}+\frac{2}{3}=\frac{x}{30-3}\)
\(\Rightarrow\frac{x}{33}+\frac{2}{3}=\frac{x}{27}\)
\(\Rightarrow\frac{x}{33}=\frac{x}{27}-\frac{18}{27}\)
\(\Rightarrow\frac{x}{33}=\frac{x-18}{27}\)
\(\Rightarrow33\left(x-18\right)=27x\)
\(\Rightarrow33x-594=27x\)
\(\Rightarrow594=6x\)
\(\Rightarrow x=99\)
Ta có:
\(\frac{x}{30+3}+\frac{2}{3}=\frac{x}{30-3}\Rightarrow\frac{x}{33}+\frac{2}{3}=\frac{x}{27}\Rightarrow\frac{9x}{297}+\frac{198}{297}=\frac{11x}{297}\Rightarrow9x+198=11x\)
\(\Rightarrow11x-9x=198\Rightarrow2x=198\Rightarrow x=198:2\Rightarrow x=99\)
Vậy x = 99