\(\frac{2x-8}{6}-\frac{3x+1}{4}=\frac{9x-2}{8}+\frac{3x-1}{12}\)
\(\Leftrightarrow\frac{4\left(2x-8\right)}{24}-\frac{6\left(3x+1\right)}{24}=\frac{3\left(9x-2\right)}{24}+\frac{2\left(3x-1\right)}{24}\)
\(\Leftrightarrow\frac{8x-32}{24}-\frac{18x+6}{24}=\frac{27x-6}{24}+\frac{6x-2}{24}\)
\(\Leftrightarrow8x-32-18x-6=27x-6+6x-2\)
\(\Leftrightarrow8x-18x-27x-6x=-6-2+32+6\)
\(\Leftrightarrow-42x=30\)
\(\Leftrightarrow x=-\frac{5}{7}\)
Giải phương trình:
\(\frac{1}{x^2-3x}+\frac{1}{x^2+3x}+\frac{1}{x^2+9x+18}+\frac{3}{8}=0\)
\(\frac{2x-8}{6}-\frac{3x-1}{4}=\frac{9x-2}{8}+\frac{3x-1}{12}\)
Phương trình chứa ẩn ở mẫu
Giai các phương trình sau
1. \(\frac{7x-3}{x-1}=\frac{2}{3}\)
2. \(\frac{5x-1}{3x+2}=\frac{5x-7}{3x-1}\)
3. \(\frac{1-x}{x+1}+3=\frac{2x+3}{x+1}\)
4. \(\frac{1-6x}{x-2}+\frac{9x+4}{x+2}=\frac{x\left(3x-2\right)+1}{x^2-4}\)
5. \(\frac{3x+2}{3x-2}-\frac{6}{2+3x}=\frac{9x^2}{9x^2-4}\)
6. \(1+\frac{1}{x+2}=\frac{12}{8-x^3}\)
giải phương trình:
\(\frac{3x+1}{2x^2+3x-2}+\frac{1}{x^2-1}=\frac{1}{x^2+3x}\)
giải phương trình sau:
a) \(\frac{3x+2}{3x-2}-\frac{6}{2+3x}=\frac{9x^2}{9x-4}\\\)
b) \(\frac{3}{5x-1}+\frac{2}{3-5x}=\frac{4}{\left(1-5x\right)\left(x-3\right)}\)
c)\(\frac{3}{1-4x}=\frac{2}{4x+1}-\frac{8+6x}{16x^2-1}\)
d) \(5+\frac{76}{x^2-16}=\frac{2x-1}{x+4}-\frac{3x-1}{4-x}\)
Giải phương trình sau
\(\frac{2x-1}{3x^2+7\:x+2}+\frac{3}{9x^2+15x+4}-\frac{2x+7}{3x^2-5x-12}=\frac{5}{x+2}\)
Bài 1: Giải các phương trình sau
a,\(\frac{4x-8}{2x^2+1}\)= 0
b, \(\frac{x^2-x-6}{x-3}\)= 0
c,\(\frac{x+5}{3x-6}\)- \(\frac{1}{2}\)=\(\frac{2x-3}{2x-4}\)
d, \(\frac{12}{1-9x^2}\)= \(\frac{1-3x}{1+3x}\)- \(\frac{1+3x}{1-3x}\)
e, \(\frac{x+5}{x-1}\)= \(\frac{x+1}{x-3}\)- \(\frac{8}{x^2-4x+3}\)
f, \(\frac{x+1}{x-2}\)- \(\frac{5}{x+2}\)= \(\frac{12}{x^2-4}\)+1
g, \(\frac{2x-5}{x-2}\)- \(\frac{3x-5}{x+1}\)= -1
Rút gọn thừa số chung :
\(.\frac{x}{3x-1}+\frac{1}{3x-1}=\frac{x}{3x+2}+\frac{3}{3x+2}\)
Đơn giản biểu thức :
\(-\frac{x}{3x+2}-\frac{3}{3x+2}+\frac{x}{3x-1}+\frac{1}{3x-1}=0\)
Giải phương trình
\(-\frac{3x-5}{\left(3x-1\right)\left(3x+2\right)}=0\)
Giải phương trình :
3x=5
\(\frac{1}{3x-1}=0\)
\(\frac{1}{3x+2}=0\)
Giai các bất phương trình sau:
a) 5x-2\(\ge\)8
b) 4+3x\(\ge\)2x+1
c) 2(x-5)<8
d) \(\frac{13x-12}{12}>\frac{9x+1}{3}-\frac{8x+1}{4}\)
g) \(\frac{1}{2}x-2>2+\frac{5}{6}x\)
h) 3c-5<3d-5
