Question

Giai phương trình :

a)\(\dfrac{2x-1}{3}-x=\dfrac{x+3}{4}+2\)

b)\(x^2-4+\left(x-9\right)\left(x-2\right)=0\)

c)\(\dfrac{x-1}{x-3}-\dfrac{1}{x+3}=\dfrac{3x+3}{x^2-9}\)

Answer 1

a: =>4(2x-1)-12x=3(x+3)+24

=>8x-4-12x=3x+9+24

=>-4x-4=3x+33

=>-7x=37

=>x=-37/7

b: =>(x-2)(x+2+x-9)=0

=>(2x-7)(x-2)=0

=>x=2 hoặc x=7/2

c: =>(x-1)(x+3)-x+3=3x+3

=>x^2+2x-3-x+3=3x+3

=>x^2+x-3x-3=0

=>x^2-2x-3=0

=>(x-3)(x+1)=0

=>x=-1