\(2x^2-x=3-6x\\ \Leftrightarrow2x^2-x-3+6x=0\\ \Leftrightarrow2x^2+5x-3=0\\ \Leftrightarrow\left(2x^2+6x\right)-\left(x+3\right)=0\\ \Leftrightarrow2x\left(x+3\right)-\left(x+3\right)=0\\ \Leftrightarrow\left(x+3\right)\left(2x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-3\\x=\dfrac{1}{2}\end{matrix}\right.\)