Question

  Giải nhanh hộ vs

Answer 1

\(a,\left(\dfrac{3}{7}\right)^2=\dfrac{3^2}{7^2}=\dfrac{9}{49}\\ \left(-\dfrac{1}{2}\right)^4=\dfrac{\left(-1\right)^4}{2^4}=\dfrac{1}{16}\\ \left(-\dfrac{3}{4}\right)^3=\dfrac{\left(-3\right)^3}{4^3}=\dfrac{-27}{16}\\ \left(-\dfrac{27}{100}\right)^0=1\)

\(b,\left(\dfrac{1}{2}\right)^3.16-\dfrac{1}{4}\\ =\dfrac{1}{8}.16-\dfrac{1}{4}\\ =\dfrac{16}{8}-\dfrac{1}{4}\\ =2-\dfrac{1}{4}\\ =\dfrac{2.4-1}{4}=\dfrac{7}{4}\)

Answer 2

a: (3/7)^2=9/49

(-1/2)^4=1/16

(-3/4)^3=-27/64

(-27/100)^0=0

b: =1/8*16-1/4=2-1/4=7/4