a: \(=\dfrac{2000\left(1999+1\right)}{2000\left(504+500\right)}=\dfrac{2000}{1004}=\dfrac{500}{251}\)
c: \(=\dfrac{72\left(1+1+1+1+1\right)+168}{2+2048-1}=\dfrac{176}{683}\)
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