Question

  Giải hộ

Answer 1

a: |x|=4

=>\(\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)

b: \(x\left(x+\dfrac{2}{3}\right)=0\)

=>\(\left[{}\begin{matrix}x=0\\x+\dfrac{2}{3}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{2}{3}\end{matrix}\right.\)