a) \(\dfrac{-7}{2}+\dfrac{-3}{7}=\dfrac{-49}{14}+\dfrac{-6}{14}=\dfrac{-49+-6}{14}=-\dfrac{55}{14}\)
b) \(\dfrac{20}{7}+\dfrac{-12}{17}+\dfrac{-6}{7}+\dfrac{-22}{17}=\left(\dfrac{20}{7}+\dfrac{-6}{7}\right)+\left(\dfrac{-12}{17}+\dfrac{-22}{17}\right)\)
\(=\dfrac{14}{7}+\dfrac{-34}{17}=2+-2=0\)
\(a,\dfrac{-7}{2}+\dfrac{-3}{7}=\dfrac{-49}{14}+\dfrac{-6}{14}=\dfrac{-55}{14}\)
\(b,\dfrac{20}{7}+\dfrac{-12}{17}+\dfrac{-6}{7}+\dfrac{-22}{17}=\dfrac{340}{119}+\dfrac{-84}{119}+\dfrac{-102}{119}+\dfrac{-154}{119}=0\)
\(#Hancutii\)





giải hộ bài 5 có hình + cách giải với ạ



