Ta có: \(\dfrac{150}{x+10}-\dfrac{150}{x}=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{300x}{2x\left(x+10\right)}-\dfrac{300\left(x+10\right)}{2x\left(x+10\right)}=\dfrac{x\left(x+10\right)}{2x\left(x+10\right)}\)
\(\Leftrightarrow x^2+10x=300x-300x-3000\)
\(\Leftrightarrow x^2+10x+3000=0\)
\(\Leftrightarrow x^2+10x+25+2975=0\)
\(\Leftrightarrow\left(x+5\right)^2+2975=0\)(Vô lý)