Question

giải hệt hộ mik với ak.

I'm unable to solve the problems for you, but I can transcribe the text and equations from the image:

**BÀI TẬP VỀ NHÀ**

**Bài 1.** Thực hiện phép tính:

1) \(-\frac{3}{10} + \frac{7}{15} \cdot \frac{8}{5}\)

2) \(-\frac{7}{12} \cdot \frac{8}{15} \cdot \frac{2}{5}\)

3) \(-\frac{9}{51} \cdot \frac{17}{6} - \frac{7}{6}\)

4) \(-\frac{4}{5} \cdot \left(-\frac{3}{4}\right) 1,5\)

**Bài 2.** Thực hiện phép tính:

1) \(\left(8 + \frac{1}{3} - \frac{3}{5}\right) - \left(5 + 0,4\right) - \left(\frac{2}{3} - 1\right)\)

2) \(\left[\left(\frac{1}{2} - \frac{1}{3}\right) 3 - 1\right] + \left(\frac{2}{3}\right)^2 \cdot \left(\frac{1}{3}\right)^2\)

**Bài 3.** Bỏ dấu ngoặc rồi tính hợp lí các tổng sau:

1) \(\frac{17}{11} - \left(\frac{6}{5} - \frac{16}{11}\right) + \frac{26}{5}\)

2) \(-0,1 + \frac{16}{9} - \left(\frac{20}{9} - 11,1\right)\)

3) \(\frac{39}{5} + \left(\frac{9}{4} - \frac{5}{4}\right) - \left(\frac{6}{7}\right)\)

4) \(0,25 - 11,2 - \left(5,75 + 8,8\right)\)

**Bài 4.** Tính hợp lí:

1) \(\frac{1}{7} + \frac{1}{7} + \frac{2}{

Answer 1

Bài 1:

1: \(-\frac{3}{10}+\frac{7}{15}\cdot\frac38=-\frac{3}{10}+\frac75\cdot\frac18\)

\(=-\frac{3}{10}+\frac{7}{40}=-\frac{12}{40}+\frac{7}{40}=-\frac{5}{40}=-\frac18\)

2: \(-\frac{7}{12}-\frac{8}{15}:\frac25\)

\(=-\frac{7}{12}-\frac{8}{15}\cdot\frac52\)

\(=-\frac{7}{12}-\frac{40}{30}=-\frac{7}{12}-\frac43=-\frac{7}{12}-\frac{16}{12}=-\frac{23}{12}\)

3: \(-\frac{9}{51}\cdot\frac{17}{6}-\frac76\)

\(=-\frac96\cdot\frac{17}{51}-\frac76\)

\(=-\frac32\cdot\frac13-\frac76=-\frac12-\frac76=-\frac36-\frac76=-\frac{10}{6}=-\frac53\)

4: \(-1\frac45:\left(-\frac34\right)\cdot1,5\)

\(=-\frac95\cdot\frac{-4}{3}\cdot\frac32\)

\(=\frac95\cdot\frac43\cdot\frac32=\frac95\cdot\frac42=\frac95\cdot2=\frac{18}{5}\)

Bài 2:

1: \(\left(8+2\frac13-\frac35\right)-\left(5+0,4\right)-\left(2\frac13-1\right)\)

\(=8+\frac73-\frac35-5-0,4-\frac73+1\)

\(=\left(8-5+1\right)+\left(-\frac35-0,4\right)\)

=4-1

=3

2: \(\left\lbrace\left\lbrack\left(\frac12-\frac13\right)\cdot3-1\right\rbrack+\left(-\frac23\right)^2\right\rbrace:\left(\frac13\right)^2\)

\(=\left\lbrace\left\lbrack\frac16\cdot3-1\right\rbrack+\frac49\right\rbrace:\frac19\)

\(=\left(\frac12-1+\frac49\right)\cdot9=\left(-\frac12+\frac49\right)\cdot9=-\frac92+4=-\frac12\)

Bài 3:

1: \(\frac{17}{11}-\left(\frac65-\frac{16}{11}\right)+\frac{26}{5}\)

\(=\frac{17}{11}-\frac65+\frac{16}{11}+\frac{26}{5}\)

\(=\frac{33}{11}+\frac{20}{5}\)

=3+4=7

2: \(\left(-0,1+\frac{16}{9}\right)-\left(\frac{20}{9}-11,1\right)\)

\(=-\frac{1}{10}+\frac{16}{9}-\frac{20}{9}+11,1\)

\(=10-\frac49=\frac{90}{9}-\frac49=\frac{86}{9}\)

3: \(\frac{39}{5}+\left(\frac94-\frac95\right)-\left(\frac54+\frac67\right)\)

\(=\frac{39}{5}+\frac94-\frac95-\frac54-\frac67\)

\(=\frac{30}{5}+\frac44-\frac67=6+1-\frac67=6+\frac17=\frac{43}{7}\)

4: \(\left(0,25-11,2\right)-\left(5,75+8,8\right)\)

=0,25-11,2-5,75-8,8

=-5,5-20

=-25,5

Bài 4:

1: \(\frac17\cdot\frac15+\frac17\cdot\frac25+\frac17\cdot\frac45\)

\(=\frac17\left(\frac15+\frac25+\frac45\right)=\frac17\cdot\frac75=\frac15\)

2: \(\frac49\cdot\frac{-1}{19}+\frac59\cdot\frac{-1}{19}\)

\(=-\frac{1}{19}\cdot\left(\frac49+\frac59\right)\)

\(=-\frac{1}{19}\cdot\frac99=-\frac{1}{19}\)