\(n_{CaCO_3}=\dfrac{10}{100}=0,1\left(mol\right)\)
PTHH: CaCO3 --to--> CaO + CO2
_______0,1----------->0,1
=>mCaO = 0,1.56 = 5,6 (g)
=> D
Câu 2
\(n_S=\dfrac{1,6}{32}=0,05\left(mol\right)\)
PTHH: S + O2 --to--> SO2
______0,05--------->0,05
=> VSO2 = 0,05.22,4 = 1,12(l)
=> C