Question

giải giúp mik nha

Answer 1

- Giả sử \(0^0< \alpha< 90^0\).

\(\sin\alpha^2+\cos\alpha^2=1\)

\(\Rightarrow\dfrac{3}{4}+\cos\alpha^2=1\)

\(\Rightarrow\cos\alpha^2=\dfrac{1}{4}\)

\(\Rightarrow\cos\alpha=\dfrac{1}{2}\)

\(\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}=\dfrac{\dfrac{\sqrt{3}}{2}}{\dfrac{1}{2}}=\sqrt{3}\)

\(\cot\alpha=\dfrac{1}{\tan\alpha}=\dfrac{1}{\sqrt{3}}=\dfrac{\sqrt{3}}{3}\)