Question

giải chi tiết

\(\dfrac{-2}{3}\) ( \(\dfrac{3}{2}\) - x ) = \(\dfrac{3}{4}\) ( \(\dfrac{1}{6}\) - \(\dfrac{2}{9}\) )

 

Answer 1

Giải j bn

Answer 2

\(WTF^3\)

Answer 3

\(-\dfrac{2}{3}\left(\dfrac{3}{2}-x\right)=\dfrac{3}{4}\left(\dfrac{1}{6}-\dfrac{2}{9}\right)\)

\(< =>-1+\dfrac{2x}{3}=\dfrac{3}{4}\left(\dfrac{3-4}{18}\right)< =>-1+\dfrac{2x}{3}=\dfrac{3}{4}.\dfrac{-1}{18}\)

\(< =>-1+\dfrac{2x}{3}=-\dfrac{1}{24}=>\dfrac{2x}{3}=-\dfrac{1}{24}+1\)

\(< =>\dfrac{2x}{3}=\dfrac{23}{24}=>48x=69=>x=\dfrac{69}{48}=\dfrac{23}{16}\)

Answer 4

Ta có: \(-\dfrac{2}{3}\left(\dfrac{3}{2}-x\right)=\dfrac{3}{4}\cdot\left(\dfrac{1}{6}-\dfrac{2}{9}\right)\)

\(\Leftrightarrow-1+\dfrac{2}{3}x=\dfrac{1}{8}-\dfrac{1}{6}=\dfrac{-1}{24}\)

\(\Leftrightarrow\dfrac{2}{3}x=\dfrac{-1}{24}+1=\dfrac{23}{24}\)

hay \(x=\dfrac{23}{16}\)