Question

Giải chi tiết giúp mk nhá

Answer 1

\(a,\dfrac{x^2}{x-3}-\dfrac{6x}{x-3}+\dfrac{9}{x-3}\\ =\dfrac{x^2-6x+9}{x-3}\\ =\dfrac{\left(x-3\right)^2}{x-3}=x-3\)

Answer 2

a: \(=\dfrac{\left(x-3\right)^2}{x-3}=x-3\)

b: \(=\dfrac{x^2+2x+1-4x}{2\left(x-1\right)\left(x+1\right)}=\dfrac{\left(x-1\right)^2}{2\left(x-1\right)\left(x+1\right)}=\dfrac{x-1}{2x+2}\)

Answer 3

a) \(\dfrac{\left(x-3\right)^2}{\left(x-3\right)}\)= x-3

b) \(\dfrac{x-1}{2x+2}\)