a, \(x-\frac{5x+2}{6}=\frac{7-3x}{4}\)
\(\frac{12x}{12}-\frac{2\left(5x+2\right)}{12}=\frac{3\left(7-3x\right)}{12}\)
\(12x-10x-4=21-9x\)
\(11x=25\)
\(x=\frac{24}{11}\)
\(b,\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
\(\frac{10x+3}{12}=\frac{15+8x}{9}\)
\(9\left(10x+3\right)=12\left(15+8x\right)\)
\(3\left(10x+3\right)=4\left(8x+15\right)\)
\(30x+9=32x+60\)
\(-2x=51\)
\(x=-\frac{51}{2}\)
\(c,\frac{x}{3}-\frac{2x+1}{2}=\frac{x}{6}-x\)
\(\frac{2x}{6}-\frac{3\left(2x+1\right)}{6}=\frac{x-6x}{6}\)
\(2x-6x-3=x-6x\)
\(x=3\)
P/s: Bn xem lại đề bài phần d nha!
=.= hk tốt!!
là \(\frac{2+x}{3}-\frac{1}{2}x=\frac{1-2x}{4}+\frac{1}{4}\)
\(\frac{2+x}{3}-\frac{1}{2}x=\frac{1+2x}{4}+\frac{1}{4}\)
\(\frac{2\left(2+x\right)}{6}-\frac{3x}{6}=\frac{1+2x+1}{4}\)
\(\frac{4+2x-3x}{6}=\frac{2x+2}{4}\)
\(\frac{4-x}{6}=\frac{x+1}{2}\)
\(2\left(4-x\right)=6\left(x+1\right)\)
\(8-2x=6x+6\)
\(-8x=-2\)
\(x=\frac{1}{4}\)
=.= hk tốt!!