Question

Giải các phương trình :

a) \(3x^2-6x-4=4\left(x-1\right)\sqrt{3x+1}\)

b) \(\sqrt{6x-1}+\sqrt{9x^2-1}=6x-9x^2\)

c) \(3\left(\sqrt{2x-1}+\sqrt{x+3}\right)-2\sqrt{2x^2+5x-3}=3x+4\)

Answer 1

x=0 ; x=2/3 - cau b 

anh giai tu giai thu

Answer 2

Giai giùm đi

Answer 3

doi ti dc ko

Answer 4

b) 9x²-1+\(\sqrt{9x^2-1}\)\(+\frac{1}{4}=6x-1+\sqrt{6x-1}+\frac{1}{4}\)

=\(\left(\sqrt{9x^2-1}+\frac{1}{2}\right)^2=\left(\sqrt{6x-1}+\frac{1}{2}\right)^2\)

(=)\(\sqrt{9x^2-1}=\sqrt{6x-1}\)

=>\(9x^2=6x\)

x=0

x=2/3

chuc anh may man , cau a voi cau c em chua giai dc