Question

giải bất phương trình : a, 2/x-2=3/x+2

b, (x-2)(x+5)=0

c, 2(x+2)-x=4

mọi người giúp mình với ạ

 

Answer 1

a: 2/(x-2)=3/(x+2)

=>3x-6=2x+4

=>x=10

b: (x-2)(x+5)=0

=>x-2=0 hoặc x+5=0

=>x=2 hoặc x=-5

c: 2(x+2)-x=4

=>2x+4-x=4

=>x=0

Answer 2

\(a,\dfrac{2}{x-2}=\dfrac{3}{x+2}\)

\(\Leftrightarrow\dfrac{2}{x-2}-\dfrac{3}{x+2}=0\)

\(\Leftrightarrow\dfrac{2\left(x+2\right)-3\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=0\)

\(\Leftrightarrow2x+4-3x+6=0\)

\(\Leftrightarrow-x+10=0\)

\(\Leftrightarrow-x=-10\)

\(\Leftrightarrow x=10\)

\(b,\left(x-2\right)\left(x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+5=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\)

\(c,2\left(x+2\right)-x=4\)

\(\Leftrightarrow2x+4-x-4=0\)

\(\Leftrightarrow x=0\)