Ta có : \(x\left(x-1\right)-\left(x+1\right)^2=4.\)
\(\Leftrightarrow x^2-x-x^2-2x-1=4\)
\(\Leftrightarrow-3x=4+1\)
\(\Leftrightarrow-3x=5\)
\(\Leftrightarrow x=-\frac{5}{3}\)
Vậy \(x=-\frac{5}{3}\)
x(x-1)-(x+1)2=4
x2-x-(x2+1)=4
x2-x-x2-1=4
x2-x2-x-1=4
-x-1=4
-x=4+1
-x=5
\(\Rightarrow x=5\)