Question

gấp ạ

bài nào cx đc

Answer 1

Câu 2: 

a: \(\dfrac{2x-1}{5}=\dfrac{-2}{3}\)

\(\Leftrightarrow6x-3=-10\)

hay \(x=-\dfrac{7}{6}\)

b: \(\left|x+\dfrac{2}{5}\right|-2x=0\)

\(\Leftrightarrow\left|x+\dfrac{2}{5}\right|=2x\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{2}{5}=2x\left(x\ge-\dfrac{2}{5}\right)\\x+\dfrac{2}{5}=-2x\left(x< -\dfrac{2}{5}\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\left(nhận\right)\\x=-\dfrac{2}{15}\left(nhận\right)\end{matrix}\right.\)