1,
a, am : an = am - n
b, 57 : 55 + 25 : 22 = 52 + 23 = 25 + 8 = 33
\(1,\\ a,a^m:a^n=a^{m-n}\left(m>n;m,n\in Z\right)\\ b,=5^2+2^3=25+8=33\\ 2,\\ a,A=\left\{10;11;12;13;14\right\}\\ A=\left\{x\in N|9< x< 15\right\}\\ b,Có:\left(901-501\right):2+1=251\left(phần.tử\right)\\ 3,\\ a,=6\cdot8-3^4:3^2+25=48-9+25=64\\ b,=135-\left[\left(116-36\right):16\right]+1\\ =135-\left(80:16\right)+1=136-5=131\\ 4,\\ a,\Rightarrow3x-5=4\\ \Rightarrow3x=9\Rightarrow x=3\\ b,\Rightarrow4\left(x-39\right)=16\\ \Rightarrow x-39=4\Rightarrow x=43\\ c,\Rightarrow3^2\cdot3^x=3^{27}:3^3\\ \Rightarrow3^{2+x}=3^{34}\\ \Rightarrow2+x=24\Rightarrow x=22\\ 5,\\ A=1+2+2^2+...+2^{2010}\\ \Rightarrow2A=2+2^2+2^3+...+2^{2011}\\ \Rightarrow2A-A=2+2^2+...+2^{2011}-1-2-...-2^{2010}\\ \Rightarrow A=2^{2011}-1=B\)
3,
a, 6 . 23 - 81 : 32 + 52
= 6 . 8 - 81 : 9 + 25
= 48 - 9 + 25
= 64
b, 135 - {[116 - (9 - 3)2] : 24} + 120
= 135 - [(116 - 62) : 16] + 1
= 135 - [(116 - 36) : 16] + 1
= 135 - (80 : 16) + 1
= 135 - 5 + 1
= 130 + 1
= 131
2,
a, C1: \(A=\left\{10;11;12;13;14\right\}\)
C2: \(A=\left\{x\in N;9< x< 15\right\}\)
b, Khoảng cách giữa 2 phần tử liền nhau là: 503 - 501 = 2
Số phần tử của tập hợp B là: (901 + 501) : 2 = 701 phần tử