Question

g) (1/2+1)*(1/3+1)*(1/4+1)*....*(1/100+1)///h) (1-1/2)*(1-1/3)*(1-1/4)*...*(1-1/2022)

Answer 1

g: \(=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot\dfrac{5}{4}\cdot...\cdot\dfrac{101}{100}=\dfrac{101}{2}\)

h: \(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot...\cdot\dfrac{2021}{2022}=\dfrac{1}{2022}\)

Answer 2

bn tham khảo nha

(1-1/2)×(1-1/3)×(1-1/4)×....×(1-1/100)

=(2/2-1/2)x(3/3-1/3)x...x(100/100-1/100)

=1/2x2/3x...x99/100

=1/100