\(\frac{3}{5}\)x = \(\frac{2}{3}\)y (1)
\(x^2\) - \(y^2\) = 38 (2)
(1) => y = \(\frac{9}{10}\) x.Thay vao (1) ---> \(x^2\) - [\(\frac{9}{10}\)x]^2 = 38 <=> \(x^2\) - \(\frac{81}{100}\)\(x^2\) = 38
<=> \(\frac{19}{100}x^2\) = 38 <=> x2 = 2.100 = 200
<=>
{x = 10 can 2 ; y = (9/10)x = 9 can 2
{x = -10 can 2 ; y = (9/10)x = - 9 can 2.