Question

fe+h2so4→fe2(so4)3+h2s+h2o ;hno2+ h2s→no+s+h2o cân bằng electron

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Answer 1

1. \(Fe+H_2SO_{4\left(đ\right)}\underrightarrow{t^o}Fe_2\left(SO_4\right)_3+H_2S+H_2O\)

\(2Fe^0\rightarrow2Fe^{+3}+6e|\times4\)

\(S^{+6}+8e\rightarrow S^{-2}|\times3\)

→ \(8Fe+15H_2SO_{4\left(đ\right)}\underrightarrow{t^o}4Fe_2\left(SO_4\right)_3+3H_2S+12H_2O\)

2. \(HNO_3+H_2S\rightarrow NO+S+H_2O\)

\(N^{+5}+3e\rightarrow N^{+2}|\times2\)

\(S^{-2}\rightarrow S^0+2e|\times3\)

→ \(2HNO_3+3H_2S\rightarrow2NO+3S+4H_2O\)