\(\dfrac{1}{3\cdot10}+\dfrac{1}{10\cdot17}+...+\dfrac{1}{38\cdot45}=\dfrac{6}{x}\)
=>\(\dfrac{1}{7}\left(\dfrac{7}{3\cdot10}+\dfrac{7}{10\cdot17}+...+\dfrac{7}{38\cdot45}\right)=\dfrac{6}{x}\)
=>\(\dfrac{1}{3}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{17}+...+\dfrac{1}{38}-\dfrac{1}{45}=\dfrac{42}{x}\)
=>42/45=42/x
=>x=45
=>Chọn A