\(F=1+2+2^2+...+2^{98}+2^{99}\)
=>2F=2+2^2+...+2^100
=>F=2^100-1
=>E=2^100-2^100+1=1
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Các câu hỏi tương tự
TÍNH
E=2^100-2^99+2^98-2^97+...+2^2-2^1
E=\(1^2+2^2+3^2+4^2+....+98^2+99^2+100^2\)
Tính E
Tính:(101+100+99+98+...+3+2+1)/(101-100+99-98+...+3-2+1)
C=1/100 - 1/100*99 - 1/99*98 - 1/98*97 - . . . -1/3*2 - 1/2*1
B= 1/2+ (1/2)^2+(1/3)^3+.......+ (1/2)^99
C=2^100-2^99+2^98-2^97+.....+ 2^2-2
D= 2^2010- 2^2009-2^2008-.....-2^2-1
E=5^3+5^6+5^9+......+ 5^2010+5^2013
2^100-2^99+2^98-2^97+...+2^2-2
3^100-3^99+3^98-3^97+...+3^2-3+1
Giúp với các bạn ơi!!!
Thu gọn tổng sau:
a) A=1+3+3^2+...+3^100
b) B=2^100-2^99+2^98-2^97+...+2^2-2
c) C=3^100-3^99+3^98-3^97+...+3^2-3+1
Rút gọn biểu thức
b) B=2^100-2^99+2^98-2^97+...+2^2-2
c) C=3^100-3^99+3^98-3^97+...+3^2-3+1
a)A=1-2+3-4+...+99-100
b)B=1-2-3+4+5-6-7+...+97-98-99+100
c)C=2100-299s-998-...-22-2-1
giup mik vs a
tính: B=1+2+3.............+98+99
giải
B=1+2+3+......+98+99
+
B=99+98+.....+2+1
2B=100+100+...+100+100 = 100.99 = B = 50.99=4950