Ta có: \(n_{CH_4}=\dfrac{6,4}{16}=0,4\left(mol\right)\)
PT: \(CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)
___0,4____0,8___0,4____0,8 (mol)
a, Ta có: \(m_{CO_2}=0,4.44=17,6\left(g\right)\)
\(m_{H_2O}=0,8.18=14,4\left(g\right)\)
b, \(V_{O_2}=0,8.22,4=17,92\left(l\right)\)
Bạn tham khảo nhé!