a, PT: \(2Zn+O_2\underrightarrow{t^o}2ZnO\)
\(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
Gọi \(\left\{{}\begin{matrix}n_{Zn}=x\left(mol\right)\\n_{Al}=y\left(mol\right)\end{matrix}\right.\) ⇒ 65x + 27y = 3,41 (1)
Ta có: \(n_{O_2}=\dfrac{0,952}{22,4}=0,0425\left(mol\right)\)
Theo PT: \(n_{O_2}=\dfrac{1}{2}n_{Zn}+\dfrac{3}{4}n_{Al}=\dfrac{1}{2}x+\dfrac{3}{4}y=0,0425\left(2\right)\)
Từ (1) và (2) \(\Rightarrow\left\{{}\begin{matrix}x=0,04\left(mol\right)\\y=0,03\left(mol\right)\end{matrix}\right.\)
Theo PT: \(\left\{{}\begin{matrix}n_{ZnO}=n_{Zn}=0,04\left(mol\right)\\n_{Al_2O_3}=\dfrac{1}{2}n_{Al}=0,015\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{ZnO}=\dfrac{0,04.81}{0,04.81+0,015.102}.100\%\approx67,92\%\\\%m_{Al_2O_3}\approx32,08\%\end{matrix}\right.\)
b, Bạn bổ sung thêm đề phần này nhé.
