$m_{O\ trong\ oxit} = 41,4 - 33,4 = 8(gam)$
$n_O = \dfrac{8}{16} = 0,5(mol)$
$2H_{oxit} + O_{oxit}\ to H_2O$
$n_{H_2SO_4} = \dfrac{1}{2}n_H = n_O = 0,5(mol)$
$m_{dd\ H_2SO_4} = \dfrac{0,5.98}{20\%} = 245(gam)$
$V_{dd\ H_2SO_4} = \dfrac{245}{1,14} = 214,91(ml)$