\(n_{AlCl_3}=\dfrac{26,7}{133,5}=0,2\left(mol\right)\)
PT: \(2Al+3Cl_2\underrightarrow{t^o}2AlCl_3\)
Theo PT: \(n_{Al}=n_{AlCl_3}=0,2\left(mol\right)\Rightarrow m_{Al}=0,2.27=5,4\left(g\right)\)
\(n_{Cl_2}=\dfrac{3}{2}n_{AlCl_3}=0,3\left(mol\right)\Rightarrow m_{Cl_2}=0,3.71=21,3\left(g\right)\)